First slide
Magnetic field due to a moving charge

A proton of energy 8eV is moving in a circular path in a uniform magnetic field. The energy of an  α- particle moving in the same magnetic field and along the same path will be-


r=mvqB=pqB=2mkqB                          p22m=k;p=2mk
It r and B are same
kqm   kpkα=q2q4mm=1     kp=kα.

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