Questions
A proton enters a magnetic field with a velocity of 2.5 x 107 m/s making angle 30° with the magnetic field. What is the force on the proton ? (Given B = 2.5T)
detailed solution
Correct option is C
F=q∨Bsinθ=1⋅6×10−192⋅5×107(2⋅5)sin30∘Talk to our academic expert!
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A charged particle of mass 2 x 10-12 kg carrying a charge of 4 x 10-9 coul is projected in a uniform magnetic field of 2 x 10-4 tesla with a velocity of 10 m/s making an angle of 60° with the magnetic field. If acceleration due to gravity in that field is zero, then length of path praversed by the particle in 1 minute is
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