First slide
Force on a charged particle moving in a magnetic field
Question

A proton enters a magnetic field with a velocity of 2.5 x 107 m/s making angle 30° with the magnetic field. What is the force on the proton ? (Given B = 2.5T)

Easy
Solution

F=qBsinθ=16×101925×107(25)sin30

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App