A proton $$(mass$$ $$=1.67$$×$$10$$−$$27kg$$ and charge $$=1.6$$×$$10$$−$$19C$$ is projected in a uniform magnetic field of $$2$$ $$Wb/m2$$ with a velocity $$3.4$$×$$107m/s$$ in a direction perpendicular to the field. The acceleration of the proton should be

Correct option is 16.5×1015m/s2

Questions

A proton (mass $= 1.67 \times 10^{- 27} kg and charge = 1.6 \times 10^{- 19} C)$ is projected in a uniform magnetic field of 2 Wb/m² with a velocity $3.4 \times 10^{7} m / s$ in a direction perpendicular to the field. The acceleration of the proton should be

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detailed solution

Correct option is A

F = ma = qvB⇒a =qvBm=1.6×10−19×2×3.4×1071.67×10−27=6.5×1015 m/s2

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A proton (mass =1.67×10−27kg and charge =1.6×10−19C is projected in a uniform magnetic field of 2 Wb/m2 with a velocity 3.4×107m/s in a direction perpendicular to the field. The acceleration of the proton should be

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A proton (mass $= 1.67 \times 10^{- 27} kg and charge = 1.6 \times 10^{- 19} C)$ is projected in a uniform magnetic field of 2 Wb/m² with a velocity $3.4 \times 10^{7} m / s$ in a direction perpendicular to the field. The acceleration of the proton should be