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A proton of mass 1.67×  1027kg and charge 1.6×  1019C is projected with a speed of 2×  106m/s at an angle of 60° to the X-axis. If a uniform magnetic field of 0.104 T is applied along Y-axis, the path of proton is

a
A circle of radius 0.2 m and time period π  ×   10−7 s
b
A circle of radius 0.1 m and time period 2π  ×   10−7 s
c
A helix of radius 0.1 m and time period 2π  ×   10−7 s
d
A helix of radius 0.2 m and time period 4π  ×   10−7 s

detailed solution

Correct option is C

Path of the proton will be a helix of radius, r= mvsin θqBwhere  θ =  Angle between B→  and  v→⇒  r=1.67  ×10−27 ×  2  ×106 ×  sin  300 1.6  ×10−19 ×  0.104=0.1  mTime  period,  T=2πmqB =2π × 1.67  ×10−27 1.6  ×10−19 ×  0.104 =  2π × 10−7 s

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