Questions
A proton of mass m and charge +e is moving in a circular orbit in a magnetic field with energy 1 Me V. What should be the energy of (mass = 4m and charge = + 2e), so that it can revolve in the path of same radius?
detailed solution
Correct option is A
r=2mKqB ⇒K ∝ q2m ⇒ KpKα = qpqα2 × mαmp ⇒ 1Kα = qp2qp2 × 4mpmp = 1 ⇒Kα =1 MeVTalk to our academic expert!
Similar Questions
A charged beam consisting of electrons and positrons enter into a region of uniform magnetic field B perpendicular to field, with a speed v. The maximum separation between an electron and a positron will be (mass of electron = mass of positron = m)
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
