A proton of mass $$1.67$$ x $$10-27$$ kg and charge $$1.67$$ x $$10-19$$ Cs projected with a speed of $$2$$×$$106$$ $$ms-1$$ at an angle of $$600$$ to the $$X-axis$$. If a uniform magnetic field of $$0.10$$ T is applied along $$Y-axis$$, the path of proton is

Question

A proton of mass $$1.67$$ x $$10-27$$ kg and charge $$1.67$$ x $$10-19$$ Cs projected with a speed of $$2$$×$$106$$ $$ms-1$$ at an angle of $$600$$ to the $$X-axis$$. If a uniform magnetic field of $$0.10$$ T is applied along $$Y-axis$$, the path of proton is

Infinity Learn · Accepted Answer

Since the proton is entering the magnetic field at some angle other than $$90o$$, its path is helix.Corresponding velocity of the proton along $$X-axis$$,$$vx=vcos60$$°$$=2$$×$$106$$×$$12=106$$ $$ms-1Due$$ to velocity component vx, the radius of the helix is described and is given by the $$relationr=mvxqB=1.6$$×$$10-27$$×$$1061.6$$×$$10-19$$×$$0.10=0.1$$ m Now, $$T=2$$$$π$$$$rvx=2$$π×$$0.1106=2$$π×$$10-7$$ s

A proton of mass 1.67 x 10^-27 kg and charge 1.67 x 10^-19 Cs projected with a speed of $2 \times 10^{6}$ ms^-1 at an angle of 60⁰to the X-axis. If a uniform magnetic field of 0.10 T is applied along Y-axis, the path of proton is

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A proton of mass 1.67 x 10-27 kg and charge 1.67 x 10-19 Cs projected with a speed of 2×106 ms-1 at an angle of 600 to the X-axis. If a uniform magnetic field of 0.10 T is applied along Y-axis, the path of proton is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A proton of mass 1.67 x 10^-27 kg and charge 1.67 x 10^-19 Cs projected with a speed of $2 \times 10^{6}$ ms^-1 at an angle of 60⁰to the X-axis. If a uniform magnetic field of 0.10 T is applied along Y-axis, the path of proton is