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Q.

A proton is moving in a circular path with kinetic energy 8 MeV in a uniform magnetic field. What will be the kinetic energy of an α-particle if it moves in a circular path of same radius in the same magnetic field?

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a

16 MeV

b

32 MeV

c

8 MeV

d

2 MeV

answer is C.

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Detailed Solution

KE=12mv2=12mω2r2=12mQBm2r2=Q2B2r22m∴  KEαKEp=2e2e2×mp4mp=1⇒KEα=8MeV
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A proton is moving in a circular path with kinetic energy 8 MeV in a uniform magnetic field. What will be the kinetic energy of an α-particle if it moves in a circular path of same radius in the same magnetic field?