Questions
A proton is moving in a circular path with kinetic energy 8 MeV in a uniform magnetic field. What will be the kinetic energy of an particle if it moves in a circular path of same radius in the same magnetic field?
detailed solution
Correct option is C
KE=12mv2=12mω2r2=12mQBm2r2=Q2B2r22m∴ KEαKEp=2e2e2×mp4mp=1⇒KEα=8MeVTalk to our academic expert!
Similar Questions
A proton and an α-particle are projected in a uniform field in a direction perpendicular to the field. If the particles move in circular paths of same radius, then the ratio of linear momentum of proton to that of α-particle is
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