First slide

Force on a charged particle moving in a magnetic field

Question

A proton moving with a constant velocity passes through a region of space without any change in its velocity. If $\vec{E}$ and $\vec{B}$ represent the electric and magnetic fields, respectively, then this region of space may have
$(i) E = 0, B = 0$ $(ii) E = 0, B \neq 0$
$(iii) E \neq 0, B = 0$ $(iv) E \neq 0, B \neq 0$

Moderate

A

i, ii and iii
B

ii, iii and iv
C

i, ii and iv
D

all

Solution

Here the proton has no acceleration, so E = B = 0. When E = 0 but $B \neq 0$ , but parallel to the motion of proton, there will be no force acting. When $E \neq 0$ and $B \neq 0$ and E, B and motion of proton (v) are mutually perpendicular, there may be no net force. Forces due to E and B cancel each other.

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