First slide

Force on a charged particle moving in a magnetic field

Question

A proton moving with velocity v is acted upon by electric field $\vec{E}$ and magnetic field $\vec{B}$ The proton will move undeflected if

Easy

A

$\vec{E}$ is perpendicular to $\vec{B}$
B

$\vec{E}$ is parallel to v and perpendicular to $\vec{B}$
C

$\vec{E}$ , $\vec{B}$ and $\vec{v}$ are mutually perpendicular and $v = \frac{E}{B}$
D

$\vec{E}$ , and $\vec{B}$ both are parallel to $\vec{v}$

Solution

When $\vec{v}, \vec{E} and \vec{B}$ are mutually perpendicular, then $|{\vec{F}}_{e}| = |{\vec{F}}_{m}|,$ and both forces are opposite to each other.

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App