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A proton and an α−particle,  accelerated through the same potential difference, enter a region of uniform magnetic field normally. If the radius of the proton orbit is 10 cm, then that of  α-orbit is

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answer is 2.

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Detailed Solution

12 mu2=Q.V  ⇒  u=2QVm,   r=uω=2QVm  ×  mQB=1B .  2VmQ∴           r∝rP=mαmp .  QPQα=4 . 12=2  ⇒  r∝=102 cm
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