A proton and an α−particle, accelerated through the same potential difference, enter a region of uniform magnetic field normally. If the radius of the proton orbit is 10 cm, then that of α-orbit is

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answer is 2.

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Detailed Solution

12 mu2=Q.V ⇒ u=2QVm, r=uω=2QVm × mQB=1B . 2VmQ∴ r∝rP=mαmp . QPQα=4 . 12=2 ⇒ r∝=102 cm

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