A proton is projected with kinetic energy $$80$$ Mev in a uniform magnetic field making an angle of $$300$$ with the field and pitch of its trajectory is found to be $$1m$$. What will be the pitch of an α$$-particle$$ if it is projected with same kinetic energy in the same magnetic field making an angle of $$60o$$ with the field?

Question

A proton is projected with kinetic energy $$80$$ Mev in a uniform magnetic field making an angle of  $$300$$ with the field and pitch of its trajectory is found to be $$1m$$. What will be the pitch of an α$$-particle$$ if it is projected with same kinetic energy in the same magnetic field making an angle of  $$60o$$ with the field?

Infinity Learn · Accepted Answer

$$12mv2=k$$⇒$$v=2km$$    Also, $$p=vcos$$θ×T∴$$p=2kmcos$$θ×$$2$$$$π$$$$mQB=2$$$$π$$$$2kB$$×m.$$cos$$θQ⇒p∞m.$$cos$$θQ∴pα$$pp=m$$αmp.QαQp.$$cos60ocos30o=4.12.1/23/2=13$$⇒pα$$=13m$$

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