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Questions  

A proton is projected with a velocity of V=2003i^+4j^m/s in a uniform magnetic field of 5K^T. Then magnitude of force experienced by the proton just after projection is 

a
12×10−14N
b
8×10−16N
c
5×10−19N
d
18×10−17N

detailed solution

Correct option is B

F→=QV→×B→=1.6×10−19×2003i^+4j^×5K^ N⇒F=8×10−16N

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