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A proton is rotating in a circular path of radius r in a uniform magnetic field of induction B with a kinetic energy 4 MeV. Then the kinetic energy of an - particle rotating in a circular path of radius 2r in the same magnetic field will be
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Correct option is B
For a charged particle of mass m carrying a charge Q, rotating in circular path of radius r in a magnetic field of induction B, speed V = rω = QBm.r∴ Kinetic energy k=12mv2=12m.QBrm2⇒k=Q2B2r22m∴kαkp=2ee2.2rr2.m4m=4⇒kα=4 x 4 Mev=16 MeVTalk to our academic expert!
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A charged beam consisting of electrons and positrons enter into a region of uniform magnetic field B perpendicular to field, with a speed v. The maximum separation between an electron and a positron will be (mass of electron = mass of positron = m)
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