A proton, within a nucleus decays into a neutron during a process called $β^{+}$ decay which occurs is some unstable nuclei. This process is represented by the equation
$_{Z}^{A} X \to_{Z -}_{1}^{A} Y + e^{+} + V_{e}$
Let $m (_{Z}^{A} X)$ represent the mass of an atom of $_{Z}^{A} X,$ and c represent the velocity of light in vaccum. Assume that $v_{e}$ is massless. The Q value of the process is given by

Question

A proton, within a nucleus decays into a neutron during a process called $β^{+}$ decay which occurs is some unstable nuclei. This process is represented by the equation

$_{Z}^{A} X \to_{Z -}_{1}^{A} Y + e^{+} + V_{e}$

Let $m (_{Z}^{A} X)$ represent the mass of an atom of $_{Z}^{A} X,$ and c represent the velocity of light in vaccum. Assume that $v_{e}$ is massless. The Q value of the process is given by

Infinity Learn · Accepted Answer

$$Q=c2$$[$$mnum($$ $$ZAX)$$−$$mnum(Z$$−$$1AY)$$−$$me+$$] By definition.Putting,$$mnuc($$ $$ZAX)=m($$ $$ZAX)$$−$$Zme+and$$ similarly for Z−$$1AY$$,we get the final result.[$$m(ZAX)$$−$$m(z$$−$$1AY)$$]$$c2$$

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