The pulley arrangements shown in the figure are identical, the mass of the rope being negligible. In case (a) mass m is lifted by attaching a mass of 2 m to the other end of the rope. In case (b) the mass m is lifted by pulling the other end of the rope with a constant downward force F = 2 mg, where g is the acceleration due to gravity. The acceleration of mass m in case (a) is :

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zero

More than that in case (b)

Less than that in case (b)

Equal to that in case (b)

answer is C.

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Detailed Solution

Case (a):a1=2mg−mg3m=g3 Case (b):a2=2mg−mgm=g

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