The pulley arrangements shown in figure are identical, the mass of the rope being negligible. In case I, the mass m is lifted by attaching a mass $$2m$$ to the other end of rope while in the second case the rope is pulled with a constant downward force F $$=$$ $$2mg$$, where g is acceleration due to gravity. The acceleration of mass m in case I is

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Infinity Learn · Accepted Answer

$$F=ma$$,$$a=gm1$$−$$m2m1+m2$$,F−$$T=0$$ and T $$=$$ $$2mg$$ also T–mg $$=$$ $$ma1$$ Finally a < $$a1$$

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