The pulley arrangements shown in figure are identical, the mass of the rope being negligible. In case I, the mass m is lifted by attaching a mass 2m to the other end of rope while in the second case the rope is pulled with a constant downward force F = 2mg, where g is acceleration due to gravity. The acceleration of mass m in case I is

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zero

more than that in case II

less than that in case II

equal to that in case II

answer is C.

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Detailed Solution

F=ma,a=gm1−m2m1+m2,F−T=0 and T = 2mg also T–mg = ma1 Finally a < a1

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