First slide

Classification of semi-conductors

Question

A pure Ge crystal has 3.0× $10^{28}$ atoms $/ m^{3}$ . It is doped by 1 part per 10 million concentration of trivalent Ga. The number density of electrons is (Given that $n_{i}$ =1.5× $10^{16} / m^{3}$

Moderate

A

$3 x 10^{21} / m^{3}$
B

$7.5 x 10^{10} / m^{3}$
C

$3.0 x 10^{15} / m^{3}$
D

$1.5 x 10^{21} / m^{3}$

Solution

$n o o f h o l e s d u e t o i m p u r i t y n_{h} = \frac{3 x 10^{28}}{10^{7}} = 3 x 10^{21} n_{e} n_{h} = {n_{i}}^{2}$

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