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In pure germanium $(n_{i} = 10^{18} / m^{3})$ crystal at 500K, $10^{24}$ atoms phosphorus are added per cubic meter. The hole concentration will be

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Correct option is C

ni2=nenh ⇒nh=101821024=10361024=1012m−3

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In pure germanium ni=1018/m3 crystal at 500K, 1024 atoms phosphorus are added per cubic meter. The hole concentration will be

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In pure germanium $(n_{i} = 10^{18} / m^{3})$ crystal at 500K, $10^{24}$ atoms phosphorus are added per cubic meter. The hole concentration will be