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Q.

A pure resistive circuit element X when connected to an AC supply of peak voltage 200V gives a peak current of 5A which is in phase with the voltage. A second circuit element Y, when connected to the same AC supply also gives the same value of peak current but the current lags behind by 900. If the series combination of X and Y is connected to the same supply, the rms value of current is

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a

102A

b

52A

c

52A

d

5A

answer is C.

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Detailed Solution

for the first case  2005=40Ω=RIf current lags by 90o  it is an inductive circuit:  2005=40Ω=XLFor series impedance  = Z=XL2+R2=402irms=2002.402=52A
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A pure resistive circuit element X when connected to an AC supply of peak voltage 200V gives a peak current of 5A which is in phase with the voltage. A second circuit element Y, when connected to the same AC supply also gives the same value of peak current but the current lags behind by 900. If the series combination of X and Y is connected to the same supply, the rms value of current is