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A pure semiconductor has equal electron and hole concentration of 1016m-3. Doping by Indium increases nh to 4.5×1022m-3. What is nein the doped semiconductor?

a
106m-3
b
1022m-3
c
10224.5×1022m-3
d
4.5×1022m-3

detailed solution

Correct option is C

nenh=n2  or  ne=n2nh=1016×10164.5×1022                                  =10324.5×1022m-3

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