Pushing force making an angle θ to the horizontal is applied on a block of weight w placed on a horizontal table. If the angle of friction is ϕ, the magnitude of force required to move the body is equal to
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a
wcosϕcos(θ-ϕ)
b
wsinϕcos(θ+ϕ)
c
wtanϕsin(θ-ϕ)
d
wsinϕtan(θ-ϕ)
answer is B.
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Detailed Solution
N=w+Fsinθ∴ fmax=μN=(tanϕ)(w+Fsinθ)To move the body, Fcosθ=fmax=(tanϕ)(w+Fsinθ)Solving this equation, we getF=wsinϕcos(θ+ϕ)