Pushing force making an angle 0 to the horizontal is applied on a block of weight W placed on a horizontal table. If the angle of friction is ϕ the magnitude of force required to move the body is equal to
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
Wcosϕcos(θ−ϕ)
b
Wsinϕcos(θ−ϕ)
c
Wtanϕsin(θ−ϕ)
d
Wsinϕtan(θ−ϕ)
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
The situation is shown in fig.From figure, tanϕ=fRor f=Rsinϕ …(1)The condition for the block (just) to move is Fcosθ=f=Rtanϕ …(2)and Fsinθ+R=Wor R=W−Fsinθ …(3)From eqs. (2) and (3)Fcosθ=(W−Fsinθ)tanϕ =Wtanϕ−Fsinθtanϕor Fcosθ+Fsinθsinϕcosϕ=WsinϕcosϕMultiplying by cos ϕ, we getFcosθcosϕ+Fsinθsinϕ=WsinϕFcos(θ−ϕ)=WsinϕF=Wsinϕcos(θ−ϕ)