Download the app

Questions  

PV3/2= constant is the relation obeyed by a perfect gas during an adiabatic process, if the initial temperature of the gas is T, then what will be the final temperature of the gas when it is compressed to half of its initial volume.

a
2T
b
4T
c
21/2 T
d
22 T

detailed solution

Correct option is C

given PV3/2=Constant, for a perfect gas  In adiabatic process relation between Pressure P and volume V is PVγ= Constant   on comparing above two equations ⇒γ=3/2  given initial teperature T1=T  final temperature T2=?  initial volume is V1=V;   final volume is V2=V2  In adiabatic process relation between temperature T and volume V is TVγ-1=Constant T1V1γ-1= T2V2γ-1  T1T2=V2V1γ-1  substituting the given values of T1,V1,V2  TT2=121/2  T2=21/2T

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at pressure P1=105Pa and volume Vi=103m3  changes to final state at Pf=132×105pa&Vf=8×103m3in an adiabatic quasi-static process, such that P3V5= constant. Consider another thermodynamic process that brings the system form the same initial state to the same final state in two steps: an isobaric expansion at Pi followed by an isochoric (is volumetric) process at volumeVf. The amount of heat supplied to the system in the two-step process is approximately


phone icon
whats app icon