The P-V diagram of a cyclic process ABCA is as shown in the figure. Choose the correct statement
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a
QA→B= negative
b
UB→C= positive
c
WCAB= negative
d
All of these
answer is D.
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Detailed Solution
During process A to B, pressure and volume both are decreasing. Therefore, temperature and, hence, internal energy of the gas will decrease (T∝PV) or ΔUA→B negative. Further ΔWA→B is also negative as the volume of the gas is decreasing. Thus, ΔQA→B is negative.In process B to C, pressure of the gas is constant while volume is increasing. Hence, temperature should increase or ΔUB→C=positive. During C to A, volume is constant while pressure is increasing. Therefore, temperature and hence, internal energy of the gas should increase or ΔUC→A= positive. During process CAB, volume of the gas is decreasing. Hence, work done by the gas is negative.