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Q.

The P-V diagram of diatomic ideal gas system going under cyclic process is shown in figure. The work done during an adiabatic process CD  is use   γ=1.4

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a

200J

b

400J

c

-500J

d

-400J

answer is C.

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Detailed Solution

PVγ= constant Work done in Adiabatic process⇒W=11−γP2V2−P1V1⇒W=11−1.4[200×3-100×4] ⇒W=−500J
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