Q.
The P-V diagram of diatomic ideal gas system going under cyclic process is shown in figure. The work done during an adiabatic process CD is use γ=1.4
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a
200J
b
400J
c
-500J
d
-400J
answer is C.
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Detailed Solution
PVγ= constant Work done in Adiabatic process⇒W=11−γP2V2−P1V1⇒W=11−1.4[200×3-100×4] ⇒W=−500J
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