First slide

Bohr's atom model

Question

As the quantum number increases, the difference of energy between consecutive energy levels:

Easy

A

decreases
B

increases
C

first decreases and then increases
D

remains the same

Solution

$Total energy for n th level = - \frac{13.6}{n^{2}} eV E_{2} - E_{1} = - 13.6 (\frac{1}{4} - \frac{1}{1}) = \frac{13.6 \times 3}{4} = 0.75 \times 13.6 eV E_{3} - E_{2} = - 13.6 (\frac{1}{9} - \frac{1}{4}) = \frac{13.6 \times 5}{36} = 0.14 \times 13.6 eV E_{4} - E_{3} = - 13.6 (\frac{1}{16} - \frac{1}{9}) = \frac{13.6 \times 7}{144} eV = 0.05 \times 13.6 eV$
Obviously, the difference of energy between consecutive energy levels decreases.

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