A quarter horse power motor runs at a speed of 600 r.p.m. Assuming 40% efficiency the work done by the motor in one rotation will be
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a
7.46 J
b
7400 J
c
7.46 ergs
d
74.6 J
answer is A.
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Detailed Solution
Motor makes 600 revolution per minute∴n=600revolutionminute=10revsec∴Time required for one revolution =110secEnergy required for one revolution = power × time = 14×746×110=74640JBut work done = 40% of input =40%×74640=40100×74640=7.46 J