In question , the capacitor is connected to a battery with terminal voltage V This connection is maintained while the dielectric slab is held in place by the application of a force F. The required force is plates of one of the capacitors so as to fill the gap, the battery remaining connected. The charge on each capacitor will be
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a
2q0[1+(1/K)]
b
q01+(1/K)
c
2q0(1+K)
d
q0(1+K)
answer is A.
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Detailed Solution
Before the introduction of dielectric, the charge on each capacitor will be the same because they are connected in series.Initial charge on each capacitor q0 = C0V0 When dielectric is introduced, C1 = C0 and C2 = K C0C=C1C2C1+C2=C0×C0KC0+C0K=C0K1+KCharge on each capacitorq=C2V0=C0K1+K2V0=2q0[1+(1/K)]