Q.
The Q-value of the fusion reaction, He 4+He 4→Be 8 is -9.315×10xeV. Find the value of x. Atomic mass of Be 8 is 8.0053u and that of He 4 is 4.0026u
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answer is 0004.00.
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Detailed Solution
Q -value =Δm×931.5MeV⇒Q=2×4.0026−8.0053×931.5MeV⇒Q=−0.09315MeV=−9.315×104eV
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