R is the radius of the earth and ω is its angular velocity and gp is the value of g at the poles. The effective value of g at the latitude λ=60° will be equal to

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gp−14Rω2

gp−34Rω2

gp−Rω2

gp+14Rω2

answer is A.

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Detailed Solution

g=gp−Rω2cos2λ=gp−ω2Rcos260°=gp−ω2R122=gp−14Rω2∵cos60°=12

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