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R is the radius of the earth and $ω$ is its angular velocity and $g_{p}$ is the value of g at the poles. The effective value of g at the latitude $λ = 60 °$ will be equal to

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detailed solution

Correct option is A

g=gp−Rω2cos2λ=gp−ω2Rcos260°=gp−ω2R122=gp−14Rω2∵cos60°=12

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R is the radius of the earth and ω is its angular velocity and gp is the value of g at the poles. The effective value of g at the latitude λ=60° will be equal to

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R is the radius of the earth and $ω$ is its angular velocity and $g_{p}$ is the value of g at the poles. The effective value of g at the latitude $λ = 60 °$ will be equal to