A radiation is emitted by 1000 W bulb and it generates an electric field and magnetic field at P, placed at a distance of 2 m. The efficiency of the bulb is 1.25%. The value of peak electric field at P is x×10−1V/m . Value of x is _______. (Round-off to the nearest integer) [Take ε0=8.85×10−12C2N−1m−2,c=3×108ms−1 ]

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answer is 137.

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Detailed Solution

Intensity =l=P4πr2=12ε0E02c⇒1.25100×10004π×4=128.85×10−12×E02×3×108⇒E02=187.2538⇒E0=13.68=136.8×10−1V/m⇒x≃137

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