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Questions  

A radiation of energy E falls normally on a perfectly reflecting surface. The momentum transferred to the surface is (C=velocity of light)

a
2EC2
b
EC2
c
EC
d
2EC

detailed solution

Correct option is D

Energy of radiation E=hv=hcλMomentum Pi=hλ=ECPr=-Pi=-ECmomentum transferred = Pi - Pr=EC--EC⇒2EC

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