A radiation of energy ‘E’ falls normally on a perfectly reflecting surface. The momentum transferred to the surface is (C = Velocity of light )

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2EC2

EC2

2EC

answer is D.

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Detailed Solution

Energy of radiation, E=hv=hCλ Also, its momentum p=hλ=EC=pipr=-pi=-ECSo, momentum transferred to the surface =pi-pr=EC--EC=2EC

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