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A radiation of energy ‘E’  falls normally on a perfectly reflecting surface. The momentum transferred to the surface is (C =  Velocity of light )

 

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a
2EC2
b
EC2
c
EC
d
2EC

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detailed solution

Correct option is D

Energy of radiation, E=hv=hCλ Also, its momentum p=hλ=EC=pipr=-pi=-ECSo, momentum transferred to the surface =pi-pr=EC--EC=2EC


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