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The radii of curvature of the two surfaces of a lens are 20 cm and 30 cm and the refractive index of the material of the lens is 1.5. If the lens is concave -convex , then the focal length of the lens is

a
24 cm
b
10 cm
c
15 cm
d
120 cm

detailed solution

Correct option is D

1f=μ−11R1−1R21f=1.5−1120−1301f=0.530−20600    or1f=12×10600=1120    orf=120  cm

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