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Q.

The radii of curvature of the two surfaces of a lens are 20 cm and 30 cm and the refractive index of the material of the lens is 1.5. If the lens is concave -convex , then the focal length of the lens is

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a

24 cm

b

10 cm

c

15 cm

d

120 cm

answer is D.

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Detailed Solution

1f=μ−11R1−1R21f=1.5−1120−1301f=0.530−20600    or1f=12×10600=1120    orf=120  cm
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