Questions

The radii of curvatures of convex surface, concave surface of a concavo-convex lens are in the ratio 1 : 2. The refractive index of the material of lens is 5/4 and its focal length is 40 cm. This lens is cut into a plano-convex lens and plano-concave lens. If the plano convex lens is immersed in water then its focal length is

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+ 20 cm

-20 cm

+ 80 cm

-80 cm

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detailed solution

Correct option is D

1f=μ−11R−12R140=54−112RR=5 cm1f2=μμw−11R1f2=5/44/3−115=-180f2=-80 cm

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A convex lens is at a distance of 10 cm from a convex mirror of focal length 10 cm as shown in figure. A beam of light parallel to the principal axis is incident on the tens. After refraction through the lens, reflection at the mirror and again refraction through the lens, the final emergent beam refraces the path of the incident beam then focal length of the lens is