First slide

Radio activity

Question

Radioactive element decays to form a stable nuclide, then the rate of decay of reactant $(\frac{dN}{dt})$ will vary with time (t) as shown in figure.

Moderate

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B
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D

Solution

$N = N_{0} e^{- λt} \Rightarrow \frac{dN}{dt} = - N_{0} {λe}^{- λt}$
i.e., Rate of decay $(\frac{dN}{dt})$ varies exponentially with time (t).

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