First slide

Radio activity

Question

A radioactive element has a half life of 2.5 hours. In 10 hours 1 gm of radioactive material is reduced to

Easy

A

1/4 gm
B

1/8 gm
C

1/16 gm
D

1/32 gm

Solution

$N = \frac{N_{0}}{{(2)}^{\frac{t}{T}}} \Rightarrow m = \frac{m_{0}}{{(2)}^{\frac{t}{T}}}$ ; Here m is the mass of radio active material.
$∴ I_{n} 10 hours m = \frac{m_{0}}{{(2)}^{\frac{10}{2.5}}} = \frac{1}{{(2)}^{4}} g m = \frac{1}{16} g m$

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