First slide

Radio activity

Question

99% of a radioactive element will decay between

Moderate

A

6 and 7 half-lives
B

7 and 8 half-lives
C

8 and 9 half-lives
D

9 half-lives

Solution

$N = N_{0} {(\frac{1}{2})}^{n} \Rightarrow \frac{N}{N_{0}} = {(\frac{1}{2})}^{n} \Rightarrow \frac{1}{100} = {(\frac{1}{2})}^{n} \Rightarrow 2^{n} = 100 .$
n comes out in between 6 and 7.

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