First slide

Radio activity

Question

A radioactive material has an initial amount 16 gm. After 120 days it reduces to 1 gm, then the half-life of radioactive material is

Easy

A

60 days
B

30 days
C

40 days
D

240 days

Solution

$\frac{N}{N_{0}} = {(\frac{1}{2})}^{n} \Rightarrow (\frac{1}{16}) = (\frac{1}{16}) = {(\frac{1}{2})}^{n} \Rightarrow n = 4 also n = \frac{t}{T_{1 / 2}} \Rightarrow T_{1 / 2} = \frac{120}{4} = 30 days$

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