A radioactive sample with a half life of 1 yr has the label 'active = 5μ curie on 1−9−2018'. Then, what would be its activity two years earlier ?

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0.5 μ curie

10 μ curie

20 μ curie

50 μ curie

answer is C.

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Detailed Solution

Given, activity A1=−λN0=5μ curie 2 yr earlier, the number of half-life=21=2=−λ4N0 So, A2A1=−λ4N0−λN0⇒A25=4⇒A2=20μ curie

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