A radioactive substance has a half life of four months. Three fourth of the substance will decay in

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Three

Four months

Eight months

Twelve months.

answer is C.

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Detailed Solution

Substance left undecayed=N0−34N0=14N0 NN0=14=(12)n ∴n=2i.e. In two half lives. ∴t=nT=2×4=8 months

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