First slide

Radio activity

Question

A radioactive substance has a half-life of 1 year. The fraction of this material, that would remain after 5 years will be

Easy

A

$\frac{1}{32}$
B

$\frac{1}{5}$
C

$\frac{1}{2}$
D

$\frac{4}{5}$

Solution

Number of half-lives $n = \frac{5}{1} = 5$
$Now \frac{N}{N_{0}} = {(\frac{1}{2})}^{n} \Rightarrow \frac{N}{N_{0}} = {(\frac{1}{2})}^{5} = \frac{1}{32}$

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