First slide

Radio activity

Question

The radioactivity of a certain radioactive element drops to 1/64 of its initial value in 30 seconds. Its half-life is

Easy

A

2 seconds
B

4 seconds
C

5 seconds
D

6 seconds

Solution

$N = N_{0} {(\frac{1}{2})}^{t / T} \Rightarrow \frac{N_{0}}{64} = N_{0} {(\frac{1}{2})}^{30 / T} \Rightarrow T = \frac{30}{6} = 5 \sec$

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