First slide

Radio activity

Question

A radio-isotope has a half-life of 5 years. The fraction of the atoms of this material that would decay in 15 years will be

Moderate

A

1/8
B

⅔
C

7/8
D

5/8

Solution

$\frac{N}{N_{0}} = {(\frac{1}{2})}^{15 / 5} = \frac{1}{8} \Rightarrow Decayed fraction = 1 - \frac{1}{8} = \frac{7}{8}$

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