First slide

Accuracy; precision of instruments and errors in measurements

Question

The radius of a ball is $(5.2 \pm 0.2) cm$ . The percentage error in the volume of the ball is approximately

Easy

A

11%
B

4%
C

7%
D

9%

Solution

Radius of ball = $5.2 cm$
$V = \frac{4}{3} π R^{3}$
$\frac{Δ V}{V} = 3 (\frac{Δ R}{R})$
$(\frac{Δ V}{V}) \times 100 = 3 (\frac{0.2}{5.2}) \times 100 = 11 %$

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