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The radius of the Bohr orbit in the ground state of hydrogen atom is 0.5A0 . Then the radius of the orbit of the electron in the third excited state of He+ ion is

a
2A0
b
4A0
c
6A0
d
8A0

detailed solution

Correct option is B

rn=r0.n2Z,where  r0=radius  of  bohr  orbit∴ For  He+ion,r4=0.5×422A0=4A0

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