The radius of the circular conducting loop shown in figure is R. Magnetic field is decreasing at a constant rate α. Resistance per unit length of the loop is ρ.Then, the current in wire AB is (AB is one of the diameters)
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a
Rα2ρ from A to B
b
Rα2ρ from B to A
c
Rαρ from A to B
d
0
answer is D.
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Detailed Solution
According to Lenz's law, emf of same magnitude in clockwise direction is induced in the two loops into which the figure is divided. So, current is induced in the clockwise direction in the outer boundary but no current is there in wire AB.
The radius of the circular conducting loop shown in figure is R. Magnetic field is decreasing at a constant rate α. Resistance per unit length of the loop is ρ.Then, the current in wire AB is (AB is one of the diameters)