First slide
Force on a charged particle moving in a magnetic field
Question

The radius of the circular path or helical path followed by the test charge qo moving in magnetic field B with some velocity v is

Easy
Solution

The circular motion of charged particle will be due to component of velocity v perpendicular to magnetic field, i.e., v sinθ
 m(vsinθ)2r=q0(vsinθ)B
or r=m(vsinθ)q0B

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