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The radius of the coil of a tangent galvanometer, which has 10 turns, is 0.1 m. The current required to produce a deflection of $60^{o} (B_{H} = 4 x 10^{- 5}) T)$ is

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3 A

1.1 A

2.1 A

1.5 A

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detailed solution

Correct option is B

B=BH tanθ⇒μ0ni2R=BH tanθ⇒i=2R.BH tanθμ0n=2 x 0.1 x 4 x 10-5x310 x 4π x 10-7=1.1 A

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The radius of the coil of a tangent galvanometer, which has 10 turns, is 0.1 m. The current required to produce a deflection of 60o (BH= 4 x 10-5) T) is

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The radius of the coil of a tangent galvanometer, which has 10 turns, is 0.1 m. The current required to produce a deflection of $60^{o} (B_{H} = 4 x 10^{- 5}) T)$ is