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Q.

Radius of curvature of the convex surface of a concavo-convex lens is 30 cm and that of the  concave surface is 20 cm. The refractive index of glass is 1.5 , the focal length of the lens is

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a

-60 cm

b

-120 cm

c

120 cm

d

60 cm

answer is C.

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Detailed Solution

R2=+30cm R1=+20cm ∴1f=(μ-1)1R1-1R2 ⇒1f=(1.5-1)1(+20)-1(+30)⇒f=+120cm.
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